2x+4y^2=128

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Solution for 2x+4y^2=128 equation: 


Simplifying
2x + 4y2 = 128

Solving
2x + 4y2 = 128

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y2' to each side of the equation.
2x + 4y2 + -4y2 = 128 + -4y2

Combine like terms: 4y2 + -4y2 = 0
2x + 0 = 128 + -4y2
2x = 128 + -4y2

Divide each side by '2'.
x = 64 + -2y2

Simplifying
x = 64 + -2y2

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